2x^2/4-x/6=3/2

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Solution for 2x^2/4-x/6=3/2 equation: 


x in (-oo:+oo)

(2*x^2)/4-(x/6) = 3/2 // - 3/2

(2*x^2)/4-(x/6)-(3/2) = 0

(2*x^2)/4-(x/6)-3/2 = 0

1/2*x^2-1/6*x-3/2 = 0

DELTA = (-1/6)^2-(-3/2*1/2*4)

DELTA = 109/36

DELTA > 0

x = ((109/36)^(1/2)+1/6)/(1/2*2) or x = (1/6-(109/36)^(1/2))/(1/2*2)

x = (109/36)^(1/2)+1/6 or x = 1/6-(109/36)^(1/2)

x in { 1/6-(109/36)^(1/2), (109/36)^(1/2)+1/6 }

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